EasySpin forum

Thanks. As you say, the effective hyperfine coupling is independent of the signs of the principal values, because the calculation of Aeff ends up as the square root of the sum of the components squared.

Hi, running pepper with negative hyperfine values for some axes gives spectra that do not match my expectations, or my own Matlab code. I will paste in an explicit example below. I expect this spectra to have a narrow central line (for 14N = 0), and the two (14N = +-1) other peaks to form a Pake dou...